Optimal. Leaf size=328 \[ -\frac{105 b e^3 (a+b x)}{8 \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (b d-a e)^5}-\frac{35 e^3 (a+b x)}{8 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)^4}-\frac{21 e^2}{8 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)^3}+\frac{3 e}{4 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)^2}-\frac{1}{3 (a+b x)^2 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)}+\frac{105 b^{3/2} e^3 (a+b x) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^{11/2}} \]
[Out]
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Rubi [A] time = 0.568091, antiderivative size = 328, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.171 \[ -\frac{105 b e^3 (a+b x)}{8 \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (b d-a e)^5}-\frac{35 e^3 (a+b x)}{8 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)^4}-\frac{21 e^2}{8 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)^3}+\frac{3 e}{4 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)^2}-\frac{1}{3 (a+b x)^2 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)}+\frac{105 b^{3/2} e^3 (a+b x) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^{11/2}} \]
Antiderivative was successfully verified.
[In] Int[(a + b*x)/((d + e*x)^(5/2)*(a^2 + 2*a*b*x + b^2*x^2)^(5/2)),x]
[Out]
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Rubi in Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: RecursionError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x+a)/(e*x+d)**(5/2)/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)
[Out]
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Mathematica [A] time = 1.191, size = 186, normalized size = 0.57 \[ \frac{(a+b x) \left (\frac{105 b^{3/2} e^3 \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{11/2}}+\frac{\sqrt{d+e x} \left (\frac{34 b^2 e (b d-a e)}{(a+b x)^2}-\frac{8 b^2 (b d-a e)^2}{(a+b x)^3}-\frac{123 b^2 e^2}{a+b x}+\frac{16 e^3 (a e-b d)}{(d+e x)^2}-\frac{192 b e^3}{d+e x}\right )}{3 (b d-a e)^5}\right )}{8 \sqrt{(a+b x)^2}} \]
Antiderivative was successfully verified.
[In] Integrate[(a + b*x)/((d + e*x)^(5/2)*(a^2 + 2*a*b*x + b^2*x^2)^(5/2)),x]
[Out]
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Maple [B] time = 0.035, size = 563, normalized size = 1.7 \[{\frac{ \left ( bx+a \right ) ^{2}}{24\, \left ( ae-bd \right ) ^{5}} \left ( 315\,\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{b \left ( ae-bd \right ) }}} \right ) \left ( ex+d \right ) ^{3/2}{x}^{3}{b}^{5}{e}^{3}+945\,\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{b \left ( ae-bd \right ) }}} \right ) \left ( ex+d \right ) ^{3/2}{x}^{2}a{b}^{4}{e}^{3}+315\,\sqrt{b \left ( ae-bd \right ) }{x}^{4}{b}^{4}{e}^{4}+945\,\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{b \left ( ae-bd \right ) }}} \right ) \left ( ex+d \right ) ^{3/2}x{a}^{2}{b}^{3}{e}^{3}+840\,\sqrt{b \left ( ae-bd \right ) }{x}^{3}a{b}^{3}{e}^{4}+420\,\sqrt{b \left ( ae-bd \right ) }{x}^{3}{b}^{4}d{e}^{3}+315\,\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{b \left ( ae-bd \right ) }}} \right ) \left ( ex+d \right ) ^{3/2}{a}^{3}{b}^{2}{e}^{3}+693\,\sqrt{b \left ( ae-bd \right ) }{x}^{2}{a}^{2}{b}^{2}{e}^{4}+1134\,\sqrt{b \left ( ae-bd \right ) }{x}^{2}a{b}^{3}d{e}^{3}+63\,\sqrt{b \left ( ae-bd \right ) }{x}^{2}{b}^{4}{d}^{2}{e}^{2}+144\,\sqrt{b \left ( ae-bd \right ) }x{a}^{3}b{e}^{4}+954\,\sqrt{b \left ( ae-bd \right ) }x{a}^{2}{b}^{2}d{e}^{3}+180\,\sqrt{b \left ( ae-bd \right ) }xa{b}^{3}{d}^{2}{e}^{2}-18\,\sqrt{b \left ( ae-bd \right ) }x{b}^{4}{d}^{3}e-16\,\sqrt{b \left ( ae-bd \right ) }{a}^{4}{e}^{4}+208\,\sqrt{b \left ( ae-bd \right ) }{a}^{3}bd{e}^{3}+165\,\sqrt{b \left ( ae-bd \right ) }{a}^{2}{b}^{2}{d}^{2}{e}^{2}-50\,\sqrt{b \left ( ae-bd \right ) }a{b}^{3}{d}^{3}e+8\,\sqrt{b \left ( ae-bd \right ) }{b}^{4}{d}^{4} \right ){\frac{1}{\sqrt{b \left ( ae-bd \right ) }}} \left ( ex+d \right ) ^{-{\frac{3}{2}}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{-{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x+a)/(e*x+d)^(5/2)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)/((b^2*x^2 + 2*a*b*x + a^2)^(5/2)*(e*x + d)^(5/2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.327708, size = 1, normalized size = 0. \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)/((b^2*x^2 + 2*a*b*x + a^2)^(5/2)*(e*x + d)^(5/2)),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x+a)/(e*x+d)**(5/2)/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)
[Out]
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GIAC/XCAS [A] time = 0.330517, size = 949, normalized size = 2.89 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)/((b^2*x^2 + 2*a*b*x + a^2)^(5/2)*(e*x + d)^(5/2)),x, algorithm="giac")
[Out]